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Updated on: 07 Aug 2018, 04:44
Originally posted by EgmatQuantExpert on 27 Apr 2017, 00:03.
Last edited by EgmatQuantExpert on 07 Aug 2018, 04:44, edited 1 time in total.
Last edited by EgmatQuantExpert on 07 Aug 2018, 04:44, edited 1 time in total.
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B
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
85%
(hard)
Question Stats:
58% (03:26) correct
42%
(03:06)
wrong
based on 90
sessions
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Not Attempted Yet
Q. PQR is an isosceles triangle such that PQ = PR. S is a point on QR such that ∠ QPS \(=50^o\). T is a point on PR such that PS = PT. Find ∠ TSR.
Thanks,
Saquib
Quant Expert
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- A. \(20^o\)
B. \(25^o\)
C. \(30^o\)
D. \(35^o\)
E. \(50^o\)
Thanks,
Saquib
Quant Expert
e-GMAT
Register for our Free Session on Number Properties (held every 3rd week) to solve exciting 700+ Level Questions in a classroom environment under the real-time guidance of our Experts
27 Apr 2017, 00:04
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Reserving this space to post the official solution. 
27 Apr 2017, 00:58
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As PS=PT, Triangle PST is an isoceles triangle and hence Angle PST=PTS=Z
So,angle SPT = 180-2Z
As PQ=PR, Triangle PQR is an isoceles triangle and hence Angle PQR=PRQ=Y
So In Triangle PQR => 2Y+50+180-2Z=180
=> 2Y+50-2Z=0
=> Y+25=Z
Now Since Sum of Interior opposite angles = Exterior adjacent Angle
Angle PQR + Angle QPS = Angle PST + Angle TSR
Y+50=Z+X
Y+50=Y+25+X
X=25
Answer is B
So,angle SPT = 180-2Z
As PQ=PR, Triangle PQR is an isoceles triangle and hence Angle PQR=PRQ=Y
So In Triangle PQR => 2Y+50+180-2Z=180
=> 2Y+50-2Z=0
=> Y+25=Z
Now Since Sum of Interior opposite angles = Exterior adjacent Angle
Angle PQR + Angle QPS = Angle PST + Angle TSR
Y+50=Z+X
Y+50=Y+25+X
X=25
Answer is B
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