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Bunuel
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Bunuel
A certain road trip was completed in two parts interrupted by an hour-long lunch break. During the first portion of the trip the average speed was 55 miles per hour and the average speed during the second part of the trip was 63 miles per hour. If the trip was 480 miles long and took a total of 8 hours (excluding the time stopped for lunch) then which of the following is the amount of time spent driving before the lunch break?

A. 2
B. 3
C. 4
D. 5
E. 6

let d=pre-break distance
d/55+(480-d)/63=8 hours
d=165 miles
165 miles/55 mph=3 hours
B
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There is an easy way to think about this problem.

Because the miles have to add up to be 480 miles, 63mph must be multiplied by a number of hours in which the units digit will equal either 5 or 0 because it has to be added to a multiple of 55mph. 5 hours is the only number to achieve that. Then don't forget the answer needs the other half! So 8-5=3 hours, thus B.
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