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27 Apr 2017, 02:27
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B
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
25%
(medium)
Question Stats:
82% (02:29) correct
18%
(02:34)
wrong
based on 251
sessions
History
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A certain road trip was completed in two parts interrupted by an hour-long lunch break. During the first portion of the trip the average speed was 55 miles per hour and the average speed during the second part of the trip was 63 miles per hour. If the trip was 480 miles long and took a total of 8 hours (excluding the time stopped for lunch) then which of the following is the amount of time spent driving before the lunch break?
A. 2
B. 3
C. 4
D. 5
E. 6
A. 2
B. 3
C. 4
D. 5
E. 6
27 Apr 2017, 02:38
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Let the time traveled AFTER lunch be x
Hence, the time traveled BEFORE lunch is 8-x
Given the speed before lunch is 55 miles/hr and post lunch is 63 miles/hr
55(8-x) + 63x = 480
440 - 55x + 63x = 480
440 + 8x = 480
8x = 480-440 = 40
Solving for x, x = 5
Hence the time traveled before the lunch break is 3(Option B)
Hence, the time traveled BEFORE lunch is 8-x
Given the speed before lunch is 55 miles/hr and post lunch is 63 miles/hr
55(8-x) + 63x = 480
440 - 55x + 63x = 480
440 + 8x = 480
8x = 480-440 = 40
Solving for x, x = 5
Hence the time traveled before the lunch break is 3(Option B)
General Discussion
27 Jul 2017, 09:32
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Total average speed = 480 / 8 hours = 60 MPH
We are looking at a weighted average (by time) speed of 55 (first part of the trip) and 63 (second part of the trip)
60 falls between these 2 speeds closer to 63. Overall relationship of time is, thus, 5x to 3x
Thus, 5x + 3x = 8x and 8x = total time (8 hours) => x = 1
From our relathionship above we know that 3x corresponds to time before the lunch (we have to take less of that time - 3x and more of time after lunch - 5x to arrive to 63 mph)
Thus, time before lunch = 3. B is the answer.
We are looking at a weighted average (by time) speed of 55 (first part of the trip) and 63 (second part of the trip)
60 falls between these 2 speeds closer to 63. Overall relationship of time is, thus, 5x to 3x
Thus, 5x + 3x = 8x and 8x = total time (8 hours) => x = 1
From our relathionship above we know that 3x corresponds to time before the lunch (we have to take less of that time - 3x and more of time after lunch - 5x to arrive to 63 mph)
Thus, time before lunch = 3. B is the answer.
Attachments
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