OFFICIAL SOLUTIONSince the number in question is semiprime, it has exactly two prime factors. There are only two cases to consider: The case in which the prime factors are the same, and the case in which they are different.
Consider the case in which the two prime factors are the same. Since we're looking for the smallest possible such positive integer (in order for the number to be highly composite), take the prime factors as 2
and 2
. The number in question will be 2∗2=4
, and it is easy to confirm that 4
has more factors (three: 1
, 2
, and 4
) than does any smaller positive integer. Any other square of a prime will still have just three total factors but will be larger than 4
and so will not be highly composite.
Now consider the case in which the two prime factors are different. Since we're still looking for the smallest possible such positive integer (in order for the number to be highly composite), take the prime factors as 2
and 3
. The number in question will be 2∗3=6
, and it is easy to confirm that 6
has more factors (four: 1
, 2
, 3
, and 6
) than does any smaller positive integer. Any other product of two distinct primes will still have exactly four total factors but will be larger than 6
and so will not be highly composite.
Thus 4
and 6
are the only two numbers that are both semiprime and highly composite. C is correct.