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Bunuel
If 3 men and 4 women are being considered for election to the executive board of a co-op, which has 3 positions, which of the following is the approximate probability that the executive board will not be all men?

A. 0.00
B. 0.03
C. 0.10
D. 0.42
E. 0.97

IMO, the selection doesn't care about the order, so there are \(3C3=1\) ways to select all men to the executive board of a co-op.

There are \(7C3\) ways to select 3 people to the executive board of a co-op.

Hence, there are \(7C3-1\) ways to select 3 people, at least one of them are women.

The approximate probability that the executive board will not be all men:
\(\frac{7C3-1}{7C3}=\frac{34}{35} \approx 0.97\)

The answer is E.
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mohshu


GMATPrepNow @brent the question asks for the probability that all will not be men..
ans shud be E..

please let me know if im going wrong anywhere..
thanks

Good catch - I completed missed the word "not" :(
I've edited my response accordingly.

Cheers and thanks,
Brent
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Bunuel
If 3 men and 4 women are being considered for election to the executive board of a co-op, which has 3 positions, which of the following is the approximate probability that the executive board will not be all men?

A. 0.00
B. 0.03
C. 0.10
D. 0.42
E. 0.97

We can essentially translate this question as- what is the probability that at least one woman will be chosen- because if one woman is chosen then that constitutes an executive board that is NOT entirely male. Apply the rule of complementary probability, or rather negate this event...1 minus the probability of ALL men being chosen.

1- 3c3/7c3 = 34/35

0.97

E.
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