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17 May 2017, 12:08
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B
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Difficulty:
55%
(hard)
Question Stats:
69% (02:35) correct
31%
(02:14)
wrong
based on 207
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A circular hoop with a radius of 12.5 inches is rolled in a straight line on a flat surface. If each revolution of the hoop requires 10 seconds to complete, approximately how many minutes are necessary to roll the hoop 75 feet across the surface?
A. 1
B. 2
C. 3
D. 4
E. 5
A. 1
B. 2
C. 3
D. 4
E. 5
22 May 2017, 18:35
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SajjadAhmad
Since the hoop has a radius of 12.5 inches, it has a circumference of:
2 x π x 12.5 = 25π = 25 x 3.14 = 78.5 inches
Since 1 foot is 12 inches, 75 feet is equivalent to 75 x 12 = 900 inches.
Thus, it will take 900/78.5 = 11.46 revolutions to roll the hoop 75 feet across the surface.
Since each revolution takes 10 seconds, 11.46 revolutions will take 114.6 seconds, or approximately 2 minutes.
Answer: B
General Discussion
18 May 2017, 00:10
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Radius of the circular hoop= 12.5 inches
Distance covered by circular hoop in 1 revolution= Circumference of Circular hoop
Circumference of circular hoop= 2\(\pi\)r= 2*\(\pi\)*12.5= 25\(\pi\)
Time require to complete 1 revolution =10sec
25\(\pi\) distance is covered in = 10sec
1 inches...........................................= 10/25\(\pi\)
75*12 inches...................................= 10/25\(\pi\)*\(\frac{75*12}{60}\) (\(\pi\)=\(\frac{22}{7}\)
After solving, time require to cover the distance= 1.9~2
Answer:B.
Kudos please if you like my explanation!
Distance covered by circular hoop in 1 revolution= Circumference of Circular hoop
Circumference of circular hoop= 2\(\pi\)r= 2*\(\pi\)*12.5= 25\(\pi\)
Time require to complete 1 revolution =10sec
25\(\pi\) distance is covered in = 10sec
1 inches...........................................= 10/25\(\pi\)
75*12 inches...................................= 10/25\(\pi\)*\(\frac{75*12}{60}\) (\(\pi\)=\(\frac{22}{7}\)
After solving, time require to cover the distance= 1.9~2
Answer:B.
Kudos please if you like my explanation!
