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21 May 2017, 03:11
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D
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Difficulty:
5%
(low)
Question Stats:
95% (01:16) correct
5%
(02:05)
wrong
based on 817
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Marion rented a car for $18.00 plus $0.10 per mile driven. Craig rented a car for $25.00 plus $0.05 per mile driven. If each drove d miles and each was charged exactly the same amount for the rental, then d equals
(A) 100
(B) 120
(C) 135
(D) 140
(E) 150
(A) 100
(B) 120
(C) 135
(D) 140
(E) 150
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21 May 2017, 03:39
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carcass
For d miles Marion's cost would be: 18 + 0.1d and Craig's cost would be 25 + 0.05d.
Since we are told that each was charged exactly the same amount then:
\(18 + 0.1d = 25 + 0.05d\);
\(0.05d=7\);
\(\frac{5}{100}*d=7\);
\(d = 140\).
Answer: D.
22 May 2017, 23:52
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Another way to look at this problem:
Marion = $18 + 10 cents per mile
Craig = $25 + 5 cents per mile
Initial fixed cost for Craig is $(25-18) = $7 more than that of Marion, but variable cost (per mile) for Craig is 5 cents less than that of Marion.
At a certain distance (d miles) for the rentals of both Marion and Craig to become equal, the initial difference of $7 (700 cents) Must be compensated by the 5 cents per mile difference
So d = 700/5 = 140 miles
Thus it takes 140 miles for the initial fixed cost difference (700 cents) to be compensated by variable per mile cost (5 cents)
Hence answer is D
Marion = $18 + 10 cents per mile
Craig = $25 + 5 cents per mile
Initial fixed cost for Craig is $(25-18) = $7 more than that of Marion, but variable cost (per mile) for Craig is 5 cents less than that of Marion.
At a certain distance (d miles) for the rentals of both Marion and Craig to become equal, the initial difference of $7 (700 cents) Must be compensated by the 5 cents per mile difference
So d = 700/5 = 140 miles
Thus it takes 140 miles for the initial fixed cost difference (700 cents) to be compensated by variable per mile cost (5 cents)
Hence answer is D
