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Ship X and ship Y are 5 miles apart and are on a collision course. Ship X is sailing directly north, and ship Y is sailing directly east. If the point of impact is 1 mile closer to the current position of ship X than to the current position of ship Y, how many miles away from the point of impact is ship Y at this time?

(A) 1
(B) 2
(C) 3
(D) 4
(E) 5

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Attachment:
ships.jpg
ships.jpg [ 26.99 KiB | Viewed 8480 times ]

Method I - test answers

If you draw a quick sketch, see figure, there is a right triangle with hypotenuse of 5.

Think: 3-4-5 right triangle?

Test values, start with C, where Y = 3.

If distance to collision point for Y = 3, then, per Pythagorean theorem, X = 4. INCORRECT. The collision point is closer to X.

But we have the numbers -- we need 3 and 4. Just need them switched.

Option D has Y = 4. If Y = 4 then X = 3, collision point is one mile closer to X than Y, and we have the answer.

Y = 4

Method II Algebra (I'm putting this method in because a similar question might not be a neat 3-4-5 right triangle)

Again, quick sketch.

Let distance from ship X to collision point = d, so
Distance from ship Y to collision point = (d + 1)

d\(^2\) + (d + 1)\(^2\)= 5\(^2\)

d\(^2\) + d\(^2\) + 2d + 1 = 25

2d\(^2\) + 2d - 24 = 0

d\(^2\) + d - 12 = 0

(d - 3) (d +4) = 0

d = 3, -4. Distance can't be negative. d = 3 = SHIP X

Ship Y is d + 1 = 4.

Answer D
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X is due North and Y are due East which forms a right-angled triangle with 5 miles being the hypotenuse.

The point of impact is 1 mile closer to X than Y hence X = 3 and Y = 4.

Answer D
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