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06 Jun 2017, 11:19
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B
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
55%
(hard)
Question Stats:
66% (02:37) correct
34%
(02:33)
wrong
based on 212
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In the circle above with center O, minor arc AC is equal in length to minor arc CF and line segment BD is parallel to line segment AF. If angle CAD = angle DAE = angle EAF, what is the measure of angle BDA?
A. 15
B. 30
C. 45
D. 60
E. 75
Attachment:
Circle_O.png [ 13.63 KiB | Viewed 6564 times ]
06 Jun 2017, 13:36
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In this problem, we can use the property :
In a circle, if two minor arcs are equal in measure, then their corresponding chords are equal in measure
Now if we join C to E, we get the Right Angled Traingle ACF
Since the minor arcs AC and CF are equal in length, correspoding chords AC and CF are also equal.
Therefore Traingle ACF is an Isocelese Right Angled Triangle.
Angle ACF = 90, Angle CAF = Angle CFA = 45
angle CAD + angle DAE + angle EAF = Angle CAF = 45
As angle CAD = angle DAE = angle EAF, then angle CAD = angle DAE = angle EAF = 15
angle BDA = angle DAE + angle EAF = 30
Answer is B
In a circle, if two minor arcs are equal in measure, then their corresponding chords are equal in measure
Now if we join C to E, we get the Right Angled Traingle ACF
Since the minor arcs AC and CF are equal in length, correspoding chords AC and CF are also equal.
Therefore Traingle ACF is an Isocelese Right Angled Triangle.
Angle ACF = 90, Angle CAF = Angle CFA = 45
angle CAD + angle DAE + angle EAF = Angle CAF = 45
As angle CAD = angle DAE = angle EAF, then angle CAD = angle DAE = angle EAF = 15
angle BDA = angle DAE + angle EAF = 30
Answer is B
02 Jul 2017, 08:29
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the correct answer is B.
the angle subtended by arc AC and arc CF are equal, as a result of which angle subtended by both the acrs at the center is 90 (180 in total as AF is the diameter).
we know that the angle subtended at the circle is half the angle subtended at the centre.
also, it is given that angle CAD = angle DAE = angle EAF.
so angle subtended at the cirecumference of the circle by arc CF is 45.
since BD is parallel to AF, angle BDA is equal to angle DAF.
angle DAF = 30 (2/3rd of angle CAF )
hence angle BAD is 30.
the angle subtended by arc AC and arc CF are equal, as a result of which angle subtended by both the acrs at the center is 90 (180 in total as AF is the diameter).
we know that the angle subtended at the circle is half the angle subtended at the centre.
also, it is given that angle CAD = angle DAE = angle EAF.
so angle subtended at the cirecumference of the circle by arc CF is 45.
since BD is parallel to AF, angle BDA is equal to angle DAF.
angle DAF = 30 (2/3rd of angle CAF )
hence angle BAD is 30.
