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haardiksharma
There is a sequence An for a positive integer n such that when An is divided by An-1 the remainder is An-2. If A2=7, A1=0, which of the following can be the value of A4?

A. 48
B. 50
C. 52
D. 56
E. 58


The series is \(A_1,A_2, A_3, A_4, .... =>0, 7, ...\)

Now \(A_3 \) divided by \(A_2 \) should give remainder as \(A_1\).
So, \(A_3 \) divided by \(7 \) should give remainder as \(0\), that is \(A_3\) can be any multiple of 7
=>\(A_3=7x\), where x is an integer.

Now \(A_4 \) divided by \(A_3 \) should give remainder as \(A_2\).
So, \(A_4 \) divided by \(7x \) should give remainder as \(7\), that is \(A_4\) will be 7 more than a multiple of 7
=>\(A_4=7x+7\), so \(A_4\) is a multiple of 7.

Only 56 is a multiple of 7 in the choices.

D
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haardiksharma
There is a sequence An for a positive integer n such that when An is divided by An-1 the remainder is An-2. If A2=7, A1=0, which of the following can be the value of A4?

A. 48
B. 50
C. 52
D. 56
E. 58

Given: There is a sequence An for a positive integer n such that when An is divided by An-1 the remainder is An-2.
Asked: If A2=7, A1=0, which of the following can be the value of A4?

When A3 is divided by A2 = 7 the remainder is A1 = 0;
A3 = 7k

When A4 is divided by A3 = 7k, the remainder is A2 = 7

A4 = 14k
Since 56 = 14*4 ; 56 is a valid answer.

IMO D
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