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Bunuel
Points Q and R are on segment PS, which has length 24. If PQ is half as long as QS, and QR is 3 times as long as RS, how long is RS?

(A) 2
(B) 3
(C) 4
(D) 8
(E) 12
Sketch a number line, find a common term, and use ratios to move the variables around.

P________Q_______________R___S

1. Take the segments in both ratios and add them to get an idea of what might be a common term.

PQ + QS = PS

QR + RS = QS

2. Two ratios are given. Both contain QS (the second, indirectly).

Use the more restrictive condition for QS. Here, that's the ratio with more "parts."

3. QS = QR + RS, and \(\frac{QR}{RS}\) = \(\frac{3}{1}\)

Let RS = x
QR = 3x
QS (total of ratio parts) = 4x

4. Set up the second proportion in terms of x, given that QS = 4x.

\(\frac{QS}{PQ}\) = \(\frac{2}{1}\) = \(\frac{4x}{2x}\)

PQ + QS = PS

2x + 4x = 6x

PS = 6x, and given that PS = 24:

6x = 24

x = 4

5. From above, RS = x, x = 4, hence RS = 4.

Check, starting with first segment PQ: If RS = 4, PQ = 8

That puts the number line values of the variables at
P = 0
Q = 8
R = 20 (QR = 3x = 12, 8+12=20)
S = 24 (RS = 4, 20+4=24)

Correct. RS is 4.

Answer C
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let PQ= a QR = b ans RS = c and the question says that PQ=1/2 (QS) therefore a= 1/2 (b+c) QR = 3 (RS) b = 3(c) and PS = a+b+c=24 , 2a=b+c therefore a=8 , 2a=b+c 16 =b+c 16=4c c=4
Therefore the answer is C
Hope this method helps.
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