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Sub 505 (Easy)|   Inequalities|                     
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2 < x <= 4 : x can have two values 3 or 4
0<= x <= 3 : x can have 4 values = 0,1,2,3,

common value = 3 ; Hence only one value for X;
Hence E
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integers are non decimal number.
2<x≤4 = 3, 4
and
0≤x≤3 -> 0, 1, 3

only 3 is common.

so only one integer.
answer: E
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How many integers x satisfy both \(2 < x \leq 4\) and \(0 \leq x \leq 3\) ?

A. 5

B. 4

C. 3

D. 2

E. 1


x is an integer.

Given ,

\(2 < x \leq 4\)

or

\(3 \leq x \leq 4\)

and \(0 \leq x \leq 3\)

Only value of x that meets both inequality is 3.

E is the best answer.
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what level question is this?
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carcass
How many integers x satisfy both \(2 < x \leq 4\) and \(0 \leq x \leq 3\) ?

A. 5

B. 4

C. 3

D. 2

E. 1
Solution:

We see that x could only be 3 if it is an integer and has to satisfy both inequalities. Therefore, there is only 1 integer value of x.

Answer: E
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From the first equation: 2< x <= 4

We get possible values as: 3 and 4

From the second equation: 0<= x <= 3

We get possbile values as 0,1,2,3

Only 3 is the value that's common between 2 equations.

Hence E is the answer
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2 < x <= 4, two solutions -> x = 3 or x = 4
0<= x <= 3, four solutions -> x = 0, 1, 2, 3

Only overlap between the two expressions is x = 3, so that's the only solution. The answer is E.
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