Bunuel
If the sum of three different prime numbers is an even number, what is the smallest of the three?
A. 2
B. 3
C. 5
D. 7
E. It cannot be determined from the information given.
If adding three prime numbers, the only way to guarantee an even result is if one of the prime numbers is 2. All other primes are odd.
If all three terms are odd, the sum is odd. If two terms are odd, and one is even, the sum is even. That "Even" must be 2.
2 + 3 + 5 = 10
3 + 5 + 7 = 15
2 + 11 + 19 = 32
7 + 13 + 17 = 37
With addition, an even number of odd terms sums to an even result.*
If there are two, four, or any even number of odd terms, the sum is even.
O + O = E, or
(O + O) + (O + 0) = E + E = E
Then ANY number of evens, added to even, sums to an even result.
Three primes that sum to an even number must therefore be some combination of
(O + O) + E, where
E = 2, the only even prime
1) (O + O) = E, then
2) E + E = E
Answer
*If odd is 2n + 1, then a pair of those terms, added, will pair the "plus 1s." That pairing eliminates the +1 which makes the term odd in the first place, i.e., (+1 +1) = 2