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Factors of 70=
1x70 ; 2x35 ; 5x14 ; 7x10

Now, given that one factor is reduced by 2 and other increased by 4 to retain same value, we know that
7x10 changed to (7-2)x(10+4) i.e. 5x14.

As number of rows increased by 4, we can deduce from above that initially there were 10 rows.

Hence, Ans D
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A store has a parking lot which contains 70 parking spaces. Each row in the parking lot contains the same number of parking spaces. The store has bought additional property in order to build an addition to the store. When the addition is built, 2 parking spaces will be lost from each row; however, 4 more rows will be added to the parking lot. After the addition is built, the parking lot will still have 70 parking spaces, and each row will contain the same number of parking spaces as every other row. How many rows were in the parking lot before the addition was built?

(A) 5
(B) 6
(C) 7
(D) 10
(E) 14

Let the number of rows = x
Let the number of parking spaces = y

x*y = 70

Four additional rows were added and two parking spaces removed

(X+4)(y-2) = 70

Plugging from the options

(D) 10 * 7 = 70

(10+4)(7-2) = 14*5 = 70


IMO (D)
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