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Bunuel
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Costs for 1 mile = g + m (cents)
=> costs for 100 miles = 100 * (g +m) cents
1 dollar = 100 cents
Hence, total cost IN DOLLAR = 100(g+m)/ 100 = g+m => answer C.

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varun4s
1 mile= g cents (For gasoline)
100 mile= 100g cents------(1)

1 mile= m cents (For gasoline)
100 mile= 100m cents------(2)

Add (1) and (2)

Total cost= 100g+ 100m cents= 100(g+m)cents

Now 1 cents= \(\frac{1}{100}\) dollar

100(g+m) cents= 100(g+m)cents*\(\frac{1}{100}\)

= (g+m) cents
Answer: C.
varun4s , I think you mean (g + m) dollars?

The question asks for dollars.

100(g+m)cents, then

\(100(g+m) cents * \frac{1 dollar}{100 cents}\)

The units "cents" cancel. Dollars are left.
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IMO Option C.

Total costs for 1 mile= g+m/100
total costs for 100 miles= g+m
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Bunuel
It costs g cents a mile for gasoline and m cents a mile for all other costs to run a car. How many dollars will it cost to run the car for 100 miles?

(A) (g + m)/100
(B) 100g + 100m
(C) g + m
(D) g + .1m
(E) g

Since the total cost per mile is (g + m) cents, or (g + m)/100 dollars, the total cost for a 100-mile trip, in dollars, is:

(g + m)/100 x 100 = g + m

Answer: C
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