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22 Oct 2017, 08:04
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D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
35%
(medium)
Question Stats:
78% (02:24) correct
22%
(02:51)
wrong
based on 228
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It is 185 miles from Binghamton to New York City. If a bus takes 2 hours to travel the first 85 miles, how long must the bus take to travel the final 100 miles in order to average 50 miles an hour for the entire trip?
(A) 60 min
(B) 75 min
(C) 94 min
(D) 102 min
(E) 112 min
(A) 60 min
(B) 75 min
(C) 94 min
(D) 102 min
(E) 112 min
22 Oct 2017, 08:09
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Bunuel
Total time for the trip \(= \frac{185}{50}\)
So time taken to travel \(100\) miles \(= \frac{185}{50}-2=\frac{85}{50} = 102\) min
Option D
General Discussion
22 Oct 2017, 08:49
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Bunuel
Average speed = \(\frac{TotalDistance}{TotalTime}\)
AND (just rearranging)
Total time = \(\frac{TotalDistance}{Average\\
Speed}\)
In miles per hour, then, the total time it would take to average 50 miles per hour:
\(\frac{185}{50}\) = 3.7 hours
The bus has already traveled for 2 hours. Subtract that, and do not worry about the rate for those 2 hours. Rate for both legs has been accounted for in the "time taken" equation.
(3.7 - 2) = 1.7 hours still left to travel
Multiply any fraction of an hour by 60 to get minutes.
Minutes still remaining to travel the last leg (100 miles) of the trip:
1.7 hrs * 60 = 102 minutes, OR
\(1\frac{7}{10} = \frac{17}{10}hrs * \frac{60min}{1hr} = (17 * 6)mins\) =
102 minutes
Answer D
