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Bunuel
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For a difference of 30 mins the corresponding change in speed is 5, next we find that the change is proportional throughout ie t/6. so the speed of the train after time t is 40+ t/6 (D).
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animesh mohanty
For a difference of 30 mins the corresponding change in speed is 5, next we find that the change is proportional throughout ie t/6. so the speed of the train after time t is 40+ t/6 (D).
Pls. Note the time is in minutes not hours.
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animesh mohanty
For a difference of 30 mins the corresponding change in speed is 5, next we find that the change is proportional throughout ie t/6. so the speed of the train after time t is 40+ t/6 (D).
Pls. Note the time is in minutes not hours.
change of 5 mph =0.083 miles per min which is achieved in 30 mins. This is the same as change of 0.041 miles per min that is achived in 15 mins. so the logic is correct.
P.S. i didn't mark the difference initially. Thank!
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calculate the speed by substituting time at t= 30 minutes.
t= 30 minutes = 1/2 hrs
E- 40+10t = 40+10*1/2 = 40+5 = 45 mph

hence E is the answer.
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Bunuel

At time t measured in minutes after the beginning of the timed period, which of the following gives the speed of the train in accordance with the table?

(A) t/6
(B) 10t
(C) 40 + t
(D) 40 + t/6
(E) 40 + 10t
I think elimination might be quicker. Find one pair of correlated numbers (time, speed), to disprove each answer. I varied it just to be careful.

(A) t/6? S = 45, t = 30
45\(\neq\)(30/6) = 5: NO

(B) 10t? S = 50, t = 60
50 \(\neq\)(10 * 60) = 600: NO

(C) 40 + t? S = 55,t = 90
55 \(\neq\) (40 + 90) = 130: NO

(D) 40 + t/6? S = 60, t = 120
60 = (40 + 120/6) = (40 + 20) = 60
First test works. Come back

(E) 40 + 10t? S = 70, t = 180
70 \(\neq\)(40 + 180) = 220: NO

By POE, D is the answer. Test it:
50 S, 60t: (40 + 60/6) = (40 + 10) = 50
45 S, 30t: (40 + 30/6) = (40 + 5) = 45

That's enough.

Answer D
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time is given in minutes and speed in m.p.h
60 min = 1 hr
in the table 60 min gives speed as 55
Answer E satisfies the condition
40 + 10(1) = 50

validation: for 90 min: t = 3/2
40 + 10(3/2)= 55
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Bunuel

At time t measured in minutes after the beginning of the timed period, which of the following gives the speed of the train in accordance with the table?

(A) t/6
(B) 10t
(C) 40 + t
(D) 40 + t/6
(E) 40 + 10t

Let’s plug in values from the table. In the first column, we have t = 0 for time and speed = 40.

We see that C, D, and E yield a speed of 40 when using 0 for t.

Testing the second column, we have t = 30 and speed = 45. Thus, we see that answers C and E do not yield 45 when t = 30. Answer choice D yields 40 + 30/6 = 45.

Answer: D
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Hi JeffTargetTestPrep

In line with some of the answers above that ave given the answer E, which is what I got as well - why are we taking the value of speed as it is, when it has a different unit compared to time? why aren't we converting it?

would really appreciate if you could throw more light here. thank you!

JeffTargetTestPrep
Bunuel

At time t measured in minutes after the beginning of the timed period, which of the following gives the speed of the train in accordance with the table?

(A) t/6
(B) 10t
(C) 40 + t
(D) 40 + t/6
(E) 40 + 10t

Let’s plug in values from the table. In the first column, we have t = 0 for time and speed = 40.

We see that C, D, and E yield a speed of 40 when using 0 for t.

Testing the second column, we have t = 30 and speed = 45. Thus, we see that answers C and E do not yield 45 when t = 30. Answer choice D yields 40 + 30/6 = 45.

Answer: D
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I had similar doubt as yours

One possible explanation of this could be -

The options given are a formula - A formula that is designed to take input of 't' in minutes and give the output in miles per hour

samriddhi1234
Hi JeffTargetTestPrep

In line with some of the answers above that ave given the answer E, which is what I got as well - why are we taking the value of speed as it is, when it has a different unit compared to time? why aren't we converting it?

would really appreciate if you could throw more light here. thank you!

JeffTargetTestPrep
Bunuel

At time t measured in minutes after the beginning of the timed period, which of the following gives the speed of the train in accordance with the table?

(A) t/6
(B) 10t
(C) 40 + t
(D) 40 + t/6
(E) 40 + 10t

Let’s plug in values from the table. In the first column, we have t = 0 for time and speed = 40.

We see that C, D, and E yield a speed of 40 when using 0 for t.

Testing the second column, we have t = 30 and speed = 45. Thus, we see that answers C and E do not yield 45 when t = 30. Answer choice D yields 40 + 30/6 = 45.

Answer: D
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i did not understood the question, can anyone explain?
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