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Bunuel
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B 72
There are six parallelograms with an area of 9 units square each.
There are four right angled triangles with an area of 4.5 units square each

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Rearranging blue areas we see that from every single of the 16 sqaures a half portion is coloured. So total coloured sqaures are 8 , hence 9*8 = 72

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There are 16 triangles of area 4.5
16*4.5 =72
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I got 72, which is B. All I did was count the triangles. There are probably more efficient ways.
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IMO B

Total area of the square is (3*4)^2= 144
If we counted the number of blue triangles on the left hand-side, we will realize they complete the blue ones on the left hand-side to make half of the total area of the square. Therefore, the shaded area is 144/2 = 72
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Bunuel

In the figure, ABCD is a square, and all the dots are evenly spaced: each vertical or horizontal distance between two adjacent dots is 3 units. Find the area of the shaded region.

A. 60
B. 72
C. 81
D. 96
E. 120

Attachment:
ldvagm_img1.jpg

If the vertical or horizontal distance between two adjacent dots is 3 units, then the square has dimensions 12 by 12
So, the area of the ENTIRE SQUARE = (12)(12) = 144

Now, notice that the square is comprised of 32 identical triangles

Since 16 of the triangles are shaded, the shaded regions represent 16/32 (aka 1/2) of the ENTIRE SQUARE

In other words, the area of the shaded region = 1/2 of 144
= 72

Answer: B

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Brent
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