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Bunuel
Ms. Jones has twice as much invested in stocks as in bonds. Last year, the stock investments paid 7.5 percent of their value and the bonds paid 10 percent of their value. If the total that both investments paid last year was $1,000, how much did Ms. Jones have invested in stocks?

(A) $3,636
(B) $4,000
(C) $7,500
(D) $8,000
(E) $10,000

We can let the amount invested in bonds = n and the amount invested in stocks = 2n. Thus, the interest earned from stocks was 0.075(2n) = 0.15n and the interest earned from bonds was 0.1n.

Since the total interest made from both investments was 1,000, we have:

0.15n + 0.1n = 1,000

0.25n = 1,000

n =1,000/0.25 = 100,000/25 = 4,000

The amount invested in bonds is n = 4,000. The amount invested in stocks is 2n = 8,000.

Answer: D
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Sorry for my poor English here... I have a question of "Ms. Jones has twice as much invested in stocks as in bonds."
Does this mean Stock=2Bond or Bond=2Stock?

I saw the explanation of "Twice as many A as B" clause in somewhere else and it means A=2B, and it seems not match the answer in this question.
How should I understand this clause?
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