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Bunuel

In the figure above, arcs PR and QS are semicircles with centers at Q and R respectively. If PQ = 5, what is the perimeter of the shaded region?

(A) 5π + 5
(B) 5π + 15
(C) 10π + 10
(D) 10π + 15
(E) 100π

Attachment:
2017-11-29_0807.png

we have r = 5 for each circle
perimeter of half circle = Pi * r

so perimeter of the shaded region = perimeter of both half circles + r1 + r2 = 2*5*pi + 5 + 5 = 10pi + 10
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Bunuel

In the figure above, arcs PR and QS are semicircles with centers at Q and R respectively. If PQ = 5, what is the perimeter of the shaded region?

(A) 5π + 5
(B) 5π + 15
(C) 10π + 10
(D) 10π + 15
(E) 100π

Attachment:
2017-11-29_0807.png

We see that the radii of both semicircles is 5.

Thus, the semicircular arc of each semicircle (half circumference) is 1/2 x 2π(5) = 5π. We also see that PQ = RS = 5. Thus the perimeter of the shaded region is:

5π + 5π + 5 + 5 = 10π + 10

Answer: C
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Hi All,

There's a great "pattern" behind this question.

Since we're dealing with 2 semi-circles, and QR represents the SAME radius in both of them, we know that the 2 semi-circles are IDENTICAL. Thus, the perimeter of the shape is made up of….

The circumference of one full circle + the diameter of that circle.

Since the radius = 5, we know….
Circumference = 2r(pi) = 10pi
Diameter = 2r = 10
Total perimeter = 10pi + 10

Final Answer:
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