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30 Nov 2017, 23:49
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C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
25%
(medium)
Question Stats:
75% (01:13) correct
25%
(01:36)
wrong
based on 28
sessions
History
Date
Time
Result
Not Attempted Yet
In a windowless cube-shaped storage room, the ceiling and 4 walls, including a door, are completely painted. The floor is not painted. If the painted area is equal to 80 square meters, what is the volume of the room, in cubic meters?
(A) 16
(B) 20
(C) 64
(D) 256
(E) 400
(A) 16
(B) 20
(C) 64
(D) 256
(E) 400
Bunuel
Five of the six surfaces are painted, that is
\(\frac{5}{6}\) of total surface area is painted
Total painted area = 80 sq m
Surface area = \(6s^2\)
\(\frac{5}{6}(6s^2) = 80\)
\(6s^2 = (80) * \frac{6}{5}\)
\(6s^2 = 96\)
\(s^2 = 16\)
\(s = 4\)
Volume in cubic meters
\(s^3 = 4^3 =\)
64
Answer
Edited, answer has changed, because previously I used the formula for area of a square rather than volume of a cube.
Sorry! Thanks, pushpitkc. I'll put my kudos on your post below. 
01 Dec 2017, 11:17
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Bunuel
The surface area of a cube without floor is four walls + ceiling => \(4a^2 + a^2 = 5a^2\)
\(5a^2 = 80\)
\(a^2 = 16\)
\(a= 4\)
The Volume of the room is \(a^3 = 64\)
Hence, the answer is C
