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The best way to do this is by alligation method.

We have A=18 and B=72
combine=40
72-40=32 and 40-18=22

32:22= 16/11. Answer E
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QZ
If Amberly wants to create a 40% saline solution combining solution A, which is an 18% saline solution and solution B, which is a 72% saline solution, what must the ratio of the volumes of solution A to solution B be to create a 40% saline solution?

a. 1/2
b. 11/16
c. 3/4
d. 1
e. 16/11

If you mix the two solutions equally, you'll end up with a solution that's exactly halfway between them. The halfway point between 18% and 72% is 45%.



(By the way, I figured that out by averaging 18 and 72. (18 + 72)/2 = 90/2 = 45.)

So, we don't want a 1:1 ratio. (D) is out.

In order to make a solution with less than 45% saline, you'd need more of the 18% solution. Since a 1:1 ratio of the solutions will have too much saline, then there must be more 18% solution than 72% solution.

The only answer with this property is (E).
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QZ
If Amberly wants to create a 40% saline solution combining solution A, which is an 18% saline solution and solution B, which is a 72% saline solution, what must the ratio of the volumes of solution A to solution B be to create a 40% saline solution?

a. 1/2
b. 11/16
c. 3/4
d. 1
e. 16/11

Method : Using Alligation



Final Solution Saline Concentration : 40 %

Initial Solution A Saline Concentration : 18%

Initial Solution B Saline Concentration : 72%


Ratio of A : B = (72 - 40) : ( 40 - 18) = 32 : 22 = 16 : 11

Thus, the correct answer is Option E.


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Deconstructing the Question

Solution A is \(18\%\), solution B is \(72\%\), and the target is \(40\%\).

We need the ratio of A to B using weighted average.

Step-by-step

Difference between B and the mean is

\(72 - 40 = 32\)

Difference between the mean and A is

\(40 - 18 = 22\)

So the ratio of A to B is

\(32:22\)

Simplify:

\(\frac{32}{22} = \frac{16}{11}\)

Answer: E
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