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01 Jan 2018, 01:39
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D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
25%
(medium)
Question Stats:
76% (02:05) correct
24%
(02:28)
wrong
based on 176
sessions
History
Date
Time
Result
Not Attempted Yet
The ratio of men to women in a certain club with 150 members is m : w and the ratio of officers to non-officers is o : n. There are 75 men in the club and there are 16 officers in the club. If two-fifteenths of female members are officers, how many male non-officers are in the club?
A. 6
B. 10
C. 65
D. 69
E. It cannot be determined from information given.
A. 6
B. 10
C. 65
D. 69
E. It cannot be determined from information given.
01 Jan 2018, 03:04
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Bunuel
As one of our solutions is 'it cannot be determined' we cannot use the answers in this question.
Therefore, we'll go for a direct calculation, a Precise approach.
Let's write down what we know, going from the start of the question:
Men + Women = 150
Men = 75 --> Women = 150 - 75 = 75
Women officers = 2/15 * Women = 2/15 * 75 = 10
male officers = 16 - 10 = 6
male non-officers = 75 - 6 = 69.
(D) is our answer.
Bunuel are we assuming that the club contains only men and women (and not, say, children)?
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01 Jan 2018, 03:24
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Bunuel
Total members 150
Men 75
So women = 150-75 = 75
16 members are officers
2/15 of women are officers
So women officers = 75 * 2/15 = 10
So men officers = 16-10 = 6
So men who are not officers = 75-6 = 69
Answer is D: 69
