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17 Jan 2018, 00:09
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E
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
15%
(low)
Question Stats:
85% (01:35) correct
15%
(01:32)
wrong
based on 98
sessions
History
Date
Time
Result
Not Attempted Yet
Jim spent $60 purchasing lattes and coffees for his coworkers. If lattes cost $6 and coffees cost $3, and Jim purchased two more coffees than lattes, how many total drinks did he purchase?
A. 6
B. 8
C. 10
D. 12
E. 14
A. 6
B. 8
C. 10
D. 12
E. 14
17 Jan 2018, 02:13
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Bunuel
From the question stem, we can get the following details
Let L be the number of lattes and C the number of coffees
\(6L + 3C = 60 -> (1)\)
As he purchases 2 more coffees than lattes,\(C = L + 2 -> (2)\)
Using (2) in (1), we get \(6L + 3(L + 2) = 60\)
\(9L + 6 = 60 => L = \frac{54}{9} = 6\) and \(C = L + 2 = 8\)
Therefore, the total number of drinks Jim purchased is 6+8 = 14(Option E)
21 Jan 2018, 14:21
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Bunuel
(# of coffees)(cost per coffee in $) +
(# of lattes)(cost per latte in $) = total cost in $ -->
(# of coffees)(3) + (# of lattes)(6) = 60
C = # of coffees
L = # of lattes
AND
# of coffees is 2 more than # of lattes:
C = L + 2
(C)(3) + (L)(6) = 60
(L + 2)(3) + 6L = 60
3L + 6 + 6L = 60
9L = 54
L = 6
C = L + 2
C = 8
Total # of drinks: 6 + 8 = 14
Answer E
