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Bunuel
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Hi,

There's not other option than try to divide by 7, then 11, then 13, to deduce that the last number is divisible by 13.

49400
494 * 100
247 * 2

Try 247 / 7 => doesn't work
Try 247 / 11 => doesn't work
Try 247 / 13 => Gives 19

Thus, 19 * 13 * 2 *(2 * 2 * 5 * 5)

We don't care for exactitude, as soon as we can see 19 and 13, the sum must be 39 (give or take one or multiple factors of 2 or 5)
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Bunuel
What is the sum of the unique prime factors of 49,400?

A. 7
B. 10
C. 27
D. 30
E. 39

49,400 = 100 x 494

We see that 100 has primes of only 2 and 5. Now we can break down 494:

494 = 2 x 247 = 2 x 13 x 19

So the sum of the unique primes is:

2 + 5 + 13 + 19 = 39

Answer: E
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