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Let \(t\) be the total hours that Tom worked in a day, of which \(n\) are regular hours and \(t-n\) are overtime hours. We are asked to find the ratio of \(\frac{(t-n)}{n}\) such that Tom's income is double.

So for Tom to earn the double of his regular rate, the number of hours that he has to work can be expressed as -
\(nx+1.375(t-n)x = 2nx\)
\(n+1.375(t-n) = 2n\)
\(1.375(t-n) = n\)
\(\frac{(t-n)}{n}=\frac{1}{1.375}=\frac{8}{11}\)


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Hi All,

This question has a number of subtle 'hints' built into it (and the answer choices) that would help you to TEST VALUES. Most of the TESTs that you could do will involve fractions though (which is part of what makes this question harder than average). Here's how you could approach it:

We're told Tom gets paid $X per hour for each of the first N hours worked...
then Tom gets paid $1.375X per hour for each additional hour thereafter.

The first "hint" is that 0.375 = 3/8, so Tom gets paid (1 3/8)X for each overtime hour. This means that making X a multiple of 8 should help to simplify the math a bit.

We're then asked for the ratio of OVERTIME hours to REGULAR hours needed to DOUBLE his daily pay.

IF....
X = 8
N = 2
Tom earns $8(2 hours) = $16 of normal pay

(1 3/8)(8) = $11/hour for each overtime hour.

To DOUBLE his normal pay, the overtime pay must ALSO equal $16, so...

$11(Z overtime hours) = $16
Z = 16/11

So the ratio of overtime hours to regular hours is...

16/11: 2

This ratio needs to be "cleaned up" though, so let's multiply both sides by 11...

16: 22

And then reduce....

8:11

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