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Two identical dice are rolled together. If the sum of the dice is 7 29 Jan 2018, 05:40
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E
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62% (00:59) correct 38% (01:03) wrong based on 130 sessions

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Two identical dice are rolled together. If the sum of the dice is 7, what is the probability that one of the numbers showing is a 4?

(A) 1/36
(B) 1/18
(C) 1/6
(D) 11/36
(E) 1/3
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E
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Two identical dice are rolled together. If the sum of the dice is 7 29 Jan 2018, 06:12
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Bunuel
Two identical dice are rolled together. If the sum of the dice is 7, what is the probability that one of the numbers showing is a 4?

(A) 1/36
(B) 1/18
(C) 1/6
(D) 11/36
(E) 1/3
Show more

When two dice are rolled together the various ways we can
get a sum of 7 are (1,6),(2,5),(3,4),(4,3),(5,2), and (6,1)

There are a total of 6 possibilities when the sum is 7, and 2 of them need a 4.
Therefore, the probability of one of the numbers showing is a 4 is \(\frac{2}{6} = \frac{1}{3}\) (Option E)
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Two identical dice are rolled together. If the sum of the dice is 7 30 Jan 2018, 11:19
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Bunuel
Two identical dice are rolled together. If the sum of the dice is 7, what is the probability that one of the numbers showing is a 4?

(A) 1/36
(B) 1/18
(C) 1/6
(D) 11/36
(E) 1/3
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The number of ways to obtain a sum of 7 when two dice are rolled is:

1,6 or 6,1
2,5 or 5,2
3,4 or 4,3

So, there are 6 total ways to obtain a sum of 7, and, of those ways, there are two outcomes in which a 4 is showing, so the probability is 2/6 = 1/3.

Answer: E
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Two identical dice are rolled together. If the sum of the dice is 7 31 Jan 2018, 05:09
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Bunuel
Two identical dice are rolled together. If the sum of the dice is 7, what is the probability that one of the numbers showing is a 4?

(A) 1/36
(B) 1/18
(C) 1/6
(D) 11/36
(E) 1/3
Show more

Solution



    • Two dices are rolled and a sum of 7 is obtained.
      o We can get a sum of 7 in the following ways.
         (1,6) (6,1)
         (5,2) (2,5)
         (4,3) (3,4)
      o Thus, total possible cases of getting a sum of seven = 6
    • We need to find out in how many cases can one of the dices show a 4.
      o From the cases shown above, we can clearly see that the total cases with 4 on one of the dices = 2
    • Thus, the required probability = Favorable Cases/Total Cases = \(\frac{2}{6} = \frac{1}{3}\)

Correct answer: Option E.

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Two identical dice are rolled together. If the sum of the dice is 7 08 Oct 2022, 10:46
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Given that Two identical dice are rolled together and the sum of the dice is 7 and We need to find what is the probability that one of the numbers showing is a 4?

Let's find the cases in which sum of the two rolls = 7. Following are the cases
(1,6), (2,5), (3,4), (4,3), (5,2), (6,1) => 6 cases

Out of these 6 cases only two cases have 4 as one of the numbers

=> Probability that one of the numbers showing is a 4 given that sum of the two rolls is 7 = \(\frac{2}{6}\) = \(\frac{1}{3}\)

So, Answer will be E
Hope it helps!

Playlist on Solved Problems on Probability here

Watch the following video to MASTER Dice Rolling Probability Problems

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Two identical dice are rolled together. If the sum of the dice is 7 13 Feb 2026, 11:40
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