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Bunuel
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Bunuel
In Country X, three digit area codes are to be given to each town. The first digit will be any number from 2-9, inclusive, the second digit can only be either 0 or 1, and the third digit can be any number from 0-9, inclusive. How many different area codes can be issued in Country X?

A. 18
B. 140
C. 144
D. 160
E. 180

Solution



    • This question can be easily solved using the filling space method.
    • We have three spaces, one space for each digit of the code: ___ ___ ___
      o We need to fill each space, as per the condition given in the question.
      o For the first place, we know that it can any number from 2 to 9
         Thus, the following cases are possible: 2,3,4,5,6,7,8,9
         Total 8 cases.
      o The second place needs to be filled with either 0 or 1.
         Total 2 cases.
      o The third place needs to be filled with any number from 0 to 9
         Thus, the following cases are possible: 0,1,2,3,4,5,6,7,8,9
         Total 10 cases.
    • Therefore, total possible codes that can be issued are = __8__ * __2__ * __10__ = 160 cases.
    • The correct answer is Option D.


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As there are three positions to fill in,

Lets us go piece by piece,
1) For the first position the place can be filled in 8C1 ways.
2) The second position can be filled in 2C1 ways.
3) The third position can be filled in 10C1 ways.

When adding individually it gives us the answer as 160.

Correct answer D
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