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01 Feb 2018, 00:38
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B
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
35%
(medium)
Question Stats:
79% (02:16) correct
21%
(02:38)
wrong
based on 143
sessions
History
Date
Time
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The value of a share of stock P and the value of a share of stock Q each increased by 16%. If the value of a share of stock P increased by 16 cents and the value of a share of stock Q increased by $1.68, what is the difference between the value of stock Q and the value of stock P before the increases?
(A) $8.00
(B) $9.50
(C) $10.00
(D) $10.50
(E) $11.02
(A) $8.00
(B) $9.50
(C) $10.00
(D) $10.50
(E) $11.02
01 Feb 2018, 01:46
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Since we have been asked to find the difference in the values of the stocks,
it is enough to calculate the difference between the increase in the stock.
This difference is $1.52($1.68 - $0.12)
If $1.52 is 16%, we have to calculate the value of 100%.
Therefore, the difference between the value before the increases must be \(\frac{1.52*100}{16} = 0.19*50\) = $9.50(Option B)
it is enough to calculate the difference between the increase in the stock.
This difference is $1.52($1.68 - $0.12)
If $1.52 is 16%, we have to calculate the value of 100%.
Therefore, the difference between the value before the increases must be \(\frac{1.52*100}{16} = 0.19*50\) = $9.50(Option B)
01 Feb 2018, 02:08
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Answer B.
Let value of Stock P be p.
According to question stem, p*.16 = $0.16
Therefore p=$1
Let value of Stock Q be q.
According to question stem, q*.16=$1.68
Therefore q = $10.5
Difference between p & q = $9.5
Answer B
Let value of Stock P be p.
According to question stem, p*.16 = $0.16
Therefore p=$1
Let value of Stock Q be q.
According to question stem, q*.16=$1.68
Therefore q = $10.5
Difference between p & q = $9.5
Answer B
