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04 Feb 2018, 21:54
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C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
25%
(medium)
Question Stats:
70% (00:57) correct
30%
(00:51)
wrong
based on 69
sessions
History
Date
Time
Result
Not Attempted Yet
If the width of a rectangle is increased by 25% while the length remains constant, the resulting area is what percent of the original area?
(A) 25%
(B) 75%
(C) 125%
(D) 225%
(E) 250%
(A) 25%
(B) 75%
(C) 125%
(D) 225%
(E) 250%
04 Feb 2018, 22:15
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Initial area = l x b = lb
New width = 25/100 x b + b = b(1 + 25/100) = b x ( 125/100 )
New area = l x b x ( 125/100 ) = lb x (125%) = 125 % of original area.
Answer is option C.
Sent from my ONE E1003 using GMAT Club Forum mobile app
New width = 25/100 x b + b = b(1 + 25/100) = b x ( 125/100 )
New area = l x b x ( 125/100 ) = lb x (125%) = 125 % of original area.
Answer is option C.
Sent from my ONE E1003 using GMAT Club Forum mobile app
05 Feb 2018, 00:22
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Bunuel
As there are no exact numbers in the question, why not pick some?
This is an Alternative approach.
Say the width is 4 (a number it is easy to increase by 25%) and the length is 1 (a very small number, easy to work with).
Then the width increased by to 5 and the new area is 5*1 = 5.
So the answer is 5/4 = 125%.
(C) is our answer.
