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05 Feb 2018, 02:12
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C
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60% (01:40) correct
40%
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based on 319
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[GMAT math practice question]
There are 5 couples. If they sit on 10 chairs around a round table such that each couple sits side by side, how many possible cases are there?
A. 256
B. 512
C. 768
D. 1,024
E. 1,080
There are 5 couples. If they sit on 10 chairs around a round table such that each couple sits side by side, how many possible cases are there?
A. 256
B. 512
C. 768
D. 1,024
E. 1,080
05 Feb 2018, 03:30
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We can find in how many ways 5 objects may be placed around a circular table: (5-1)! = 4! = 24.
Then two people in each couple may sit in two ways (AB and BA), so we should multiply 24 by 2^5
24*32 = 768
Answer C
Then two people in each couple may sit in two ways (AB and BA), so we should multiply 24 by 2^5
24*32 = 768
Answer C
07 Feb 2018, 00:47
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The number of arrangements of the 5 couples in a circle is (5-1)! = 4!. The members of each couple can be arranged in 2! ways.
Thus, the total number of arrangements is 4! * 2! * 2! * 2! * 2! * 2! = 24*2*2*2*2*2 = 768.
Therefore, the answer is C.
Answer: C
The number of arrangements of the 5 couples in a circle is (5-1)! = 4!. The members of each couple can be arranged in 2! ways.
Thus, the total number of arrangements is 4! * 2! * 2! * 2! * 2! * 2! = 24*2*2*2*2*2 = 768.
Therefore, the answer is C.
Answer: C
