Bunuel
On Monday, a depositor withdraws funds from his savings account equal to 10% of the amount on deposit, and on Friday he deposits $140. If there were no other transactions, and if the amount in the account following Friday's transaction was 125% of the original amount, how much money was originally in the account?
(A) $125
(B) $175
(C) $400
(D) $500
(E) $540
Let x = original deposit amount
\(.90x + $140 = 1.25x\)
\(.35x = $140\)
\(x=\frac{$140}{.35}=\frac{14,000}{35}=$400\)Answer C
Translating:
x = amount of original deposit
1) On Monday, a person "withdraws funds from his savings account equal to 10% of the amount on deposit..."
In other words, he
leaves 90 percent of the original money he deposited:
.90x stays in the bank on Monday
2) "[O]n Friday he deposits $140" into that account. There are no other transactions. Now, in the account, he has Monday's amount and
+$1403) . . ."the amount in the account following Friday's transaction was 125% of the original amount. . ."
After that deposit of $140, the total amount in the bank is 125 percent of the original amount:
= 1.25xEquation:
\(.90x + $140 = 1.25x\)