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X can be 15,5 or 3 if take x=3 then only D follows .
if we take x=5 both A ,B and D follows
If x=15 then A and D follows so we can see that only D is correct
How did u count that 15,5 and 3?

HI 4/x+5/x+6/x is an integer 15/x = integer
So x can take values 15 ,3 , 5 and 1
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LCM of 2,3, and 5 is 30.

We can discard fastly A, C, and E because x can be 1.

A. x/5 - discard
B. 5/x
C. x/30 - discard
D. 30/x - (LCM of 2,3, and 5)
E. x/120 - discard

Hence, 30/x must be an integer.
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4/x + 5/x + 6/x is just equal to 15/x. If that's an integer, 30/x is clearly also an integer, since it's twice as big.
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3 consecutive integers will always be divisible by 3. So if 4, 5, and 6 over x are all integers, then x must be divisible by 3. 30 is divisible by 3, therefore option D.
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After solving the equation, we get 15/X.As 15 is divided by X, so 30/X also divided by X.

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Bunuel
Which of the following must be an integer if x is a positive integer and \(\frac{4}{x} + \frac{5}{x} + \frac{6}{x}\) is an integer ?

A. x/5
B. 5/x
C. x/30
D. 30/x
E. x/120

Adding the fractions together, we have:

15/x = integer.

Thus, x must be a factor of 15. In that case, x must also be a factor of any multiple of 15, and thus 30/x will always be an integer.

Answer: D
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Adding up all the fractions we can clearly see that x must be a multiple of 3 or 5 or both. Considering all the possible cases:

A- if X were 3 this answer would not be an integer
B - same
C- x could not be bigger than 15 so this terms is not an integer
D- right answer
E - x cannot be bigger than 15, otherwise 15/x would not be an integer.

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