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Bunuel
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q= \(\frac{1}{2}\)*(6 + 7 + 5 + q)

Solving q= 18

Answer: C.
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Bunuel
If q is equal to one-half of the sum 6, 7, 5, and q, then q =

A. 9

B. 12

C. 18

D. 27

E. 36


Given : q = (6 + 7 + 5 + q)/2

2q = 18 + q

q = 18

(C)
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Bunuel
If q is equal to one-half of the sum 6, 7, 5, and q, then q =

A. 9

B. 12

C. 18

D. 27

E. 36


q = (1/2)(6 + 7 + 5 + q)

q = 9 + q/2

Multiplying by 2 we have:

2q = 18 + q

q = 18

Answer: C
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If q is one-half of 6,7,5 and q, then 6+7+5 should be equal to q.
-> 6+7+5 = 18
-> Ans: (c)
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