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Bunuel
Set M consists of all positive integers that are multiples of 4. Set N consists of all positive integers less than 100 that have a units digit of 8. How many integers do sets M and N have in common?


(A) Three
(B) Four
(C) Five
(D) Six
(E) Seven

set M consists of all the multiples of 4. on the other hand set N consists of all the digits having 8 as its unit digit.

i think it would be wiser to move on with se N. few numbers. so set N must include: 8 18 28 38 48 58 68 78 88 98. these are the elements of set N.
Now bk to the question. we have to find out common element : 1. multiple of 4 and unit digit 8.

from the listed numbers only : 8 28 48 68 88 are divisible by 4 and have unit digit of 8.

thus, our answer will be C
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Bunuel
Set M consists of all positive integers that are multiples of 4. Set N consists of all positive integers less than 100 that have a units digit of 8. How many integers do sets M and N have in common?


(A) Three
(B) Four
(C) Five
(D) Six
(E) Seven

there are 10 positive integers <100 with a units digit of 8
half of them are multiples of 4
5
C
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