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555-605 (Medium)|   Algebra|      
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AkshdeepS
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If 2 x^2 - 2x - 12 = 0 and y^2 -5y + 6 = 0 when x = - 09 Apr 2018, 10:28
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69% (01:50) correct 31% (01:55) wrong based on 251 sessions

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If \(2 x^2 - 2x - 12 = 0\) and \(y^2 - 5y + 6 = 0\) when \(x = -y\), then what is the value of \(x\) ?

a. -3
b. -2
c. 0
d. 2
e. 3
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B
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If 2 x^2 - 2x - 12 = 0 and y^2 -5y + 6 = 0 when x = - 09 Apr 2018, 14:37
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If \(2 x^2 - 2x - 12 = 0\) and \(y^2 - 5y + 6 = 0\) when \(x = -y\), then what is the value of \(x\) ?

a. -3
b. -2
c. 0
d. 2
e. 3
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• Simplify and factor the first quadratic equation
\(2 x^2 - 2x - 12 = 0\)
\(x^2 - x - 6 = 0\)
\((x - 3)(x + 2) = 0\)

\(x = 3\) OR
\(x = -2\)

• Factor the second quadratic equation
\(y^2 - 5y + 6 = 0\)
\((y - 2)(y - 3) = 0\)

\(y = 2\) OR
\(y = 3\)

• Heed the condition:
when \(x = -y\)

For values of x and y, only one pair yields

\(x = -y\)
when
\(x = -2\)and \(y = 2\)

When \(x = -y\):

\(x = -2\)

Answer B
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If 2 x^2 - 2x - 12 = 0 and y^2 -5y + 6 = 0 when x = - 09 Apr 2018, 21:31
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If \(2 x^2 - 2x - 12 = 0\) and \(y^2 - 5y + 6 = 0\) when \(x = -y\), then what is the value of \(x\) ?

a. -3
b. -2
c. 0
d. 2
e. 3
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We can get the value of x without solving quadratics.

Substitute y = -x into \(y^2 - 5y + 6 = 0\): \(x^2 + 5x + 6 = 0\).

Multiply by 2: \(2x^2 + 10x + 12 = 0\).

Subtract the first equation: \(2x^2 + 10x + 12 -(2 x^2 - 2x - 12)= 0\);

\(12x+24=0\);

\(x=-2\).

Answer: B.
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If 2 x^2 - 2x - 12 = 0 and y^2 -5y + 6 = 0 when x = - 10 Apr 2018, 04:22
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Ans B, solving for Y it gives value for Y = 2 or 3. Using equation X = -Y and solving equation 2 X^2 - 2X - 12 = 0 for X = -2, satisfies the equation hence Ans B

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If 2 x^2 - 2x - 12 = 0 and y^2 -5y + 6 = 0 when x = - 11 Apr 2018, 16:19
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If \(2 x^2 - 2x - 12 = 0\) and \(y^2 - 5y + 6 = 0\) when \(x = -y\), then what is the value of \(x\) ?

a. -3
b. -2
c. 0
d. 2
e. 3
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Dividing the first equation by 2 and solving for x, we have:

x^2 - x - 6 = 0

(x - 3)(x + 2) = 0

x = 3 or x = -2

Solving for y in the second equation, we have:

(y - 3)(y - 2) = 0

y = 3 or y = 2

Since x = -y, we see that x must be -2 (and y must be 2).
Alternate Solution:

Note that 2x^2 can also be expressed as 2x^2 = 2x + 12 using the first equation.

Since x = -y, let’s substitute y = -x in the second equation:

(-x)^2 -5(-x) + 6 = 0

x^2 + 5x + 6 = 0

Let’s multiply each side of this equality by 2:

2x^2 + 10x + 12 = 0

2x^2 = -10x - 12

Since we have two expressions for 2x^2, let’s set them equal to each other:

2x + 12 = -10x -12

12x = -24

x = -2

Answer: B
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If 2 x^2 - 2x - 12 = 0 and y^2 -5y + 6 = 0 when x = - 11 Aug 2025, 10:40
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