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Learn structured approach to identify permutation and combination question - Exercise Question #3

There are 7 participants in a race of 400m. In how many ways can 3 different prizes be distributed to the top 3 winners?

Options:
A. 35
B. 140
C. 210
D. 280
E. 300

7C3*3! --> 7!/(4!3!)*3! = 210 --> option C.

imo, answer is option C.
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Selecting top 3 winners out of 7 participants in 7C3 ways.

Now the first winner has the opportunity to get any 1 out 3 prizes. Hence 3 options.
Similarly the second one has 2 and the last one has 1.

Therefore, 7C3*3*2*1=210.
IMO C.
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Hey everyone,

The official solution to the question has been posted. :-)

Regards,
Ashutosh
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Since there are 7 participants, the 3 different persons can be chosen in 7C3 ways.
now, 1st,2nd,3rd three rank can be allotted in 3! ways.
so total no of cases = 7C3*3! = 210 ways.
correct answer C
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