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Bunuel
How many integers n satisfy the absolute value inequality |4n - 3| <= 2

(A) One
(B) Two
(C) Three
(D) Four
(E) Five

We first solve for n for when (4n - 3) is positive:

4n - 3 ≤ 2

4n ≤ 5

n ≤ 5/4

Now we can solve for n when (4n - 3) is negative:

-(4n - 3) ≤ 2

-4n + 3 ≤ 2

-4n ≤ -1

n ≥ 1/4

So 1/4 ≤ n ≤ 5/4, and the only integer in this range is 1.

Answer: A
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Bunuel
How many integers n satisfy the absolute value inequality |4n - 3| <= 2

(A) One
(B) Two
(C) Three
(D) Four
(E) Five


Bunuel gmatbusters : Shouldnot it be B) Two i.e 0 & 1 ???

4n-3 <=2 , n=1
3-4n <=2 , n=0
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|4n - 3| <= 2
  • if 4n-3>=0 or n>=3/4 or 0.75, inequality reduces to
    4n-3 <=2
    or, 4n<=5
    or, n <=5/4 or 1.25
    hence the integer value shall be 1
  • if 4n-3<=0 or n<=3/4 or 0.75, inequality reduces to
    3-4n <=2
    4n>=1
    n>=1/4 or 1.25
    But our assumption was n<=0.75
hence no integer will satisfy n<= 0.75 and n>= 1.25
No solution

So, there is only one Solution - A

merajul
Bunuel
How many integers n satisfy the absolute value inequality |4n - 3| <= 2

(A) One
(B) Two
(C) Three
(D) Four
(E) Five


Bunuel gmatbusters : Shouldnot it be B) Two i.e 0 & 1 ???

4n-3 <=2 , n=1
3-4n <=2 , n=0
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