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If (-20) + (-19) + (-18) + (-17) + . . . + (-2x - 4) = 90, what is the value of x?
A) -24
B) -14
C) -10
D) 10
E) 14

*kudos for all correct solutions

We know that this sequence of consecutive integers starting from -20 and ending at -2x - 4 will give us 90.

Since we have the sum of consecutive integers giving us 90 as a sum and the sequence starts with -20,
the sum of these consecutive integers will be 0 if the sequence ends at 20 as -20 is canceled by 20, 19
cancels -19, 18 cancels -18........., and 1 cancels -1.

Now, the sum of the consecutive integers 21,22,23, and 24 is 90

Since the last number in the series is -2x - 4, \(-2x - 4 = 24\) -> \(-2x = 28\)

Therefore, the value of x is \(\frac{28}{-2}\) or -14(Option B)
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­For total of consecutive numbers from -20 to (-2x-4) to be 90, then it must be that

(-20) + (-19) + ... + (-1) + 0 + 1 + ... + 19 + 20 + 21 + ... + (-2x-4)

-2x-4 > 20
==> 2x + 4 < -20
==> x + 2 < -10
==> x < - 12

So x is either - 14 or - 24

Try x = -14 => -2x - 4 = 28 - 4 = 24

21 + 22 + 23 + 24 = 90

Answer is B 
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karishma, can we not use the Average * Number of terms concept here?
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