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Bunuel
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Solution




Given:
\(• There are 10 persons in a class.\\
• The score of each person of the class is between 1 and 10, inclusive.\\
• The range of the score earned by the all the 10 persons is 8.\\
\\
To find:\\
• We need to find the the lowest averagSe score possible for the class.\)

Approach and Working:

We will get the lowest average of the class if all the persons score the lowest possible score.
Between 1 to 10, the lowest score is 1."]"

Hence, nine students of the class scores 1 and one student scores 9 as range must be 9.
• Thus, average= 9*1+1*9/10= 18/10= 1.8
Hence, option B is the correct answer."
Answer: B

Thanks for the explanation but the question says that each student in the class earned an INTEGER score... From this line I expected that even the extremes of the scores should be integers. Or am I wrong?
Please Bunuel, help me out.
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Kem12


Thanks for the explanation but the question says that each student in the class earned an INTEGER score... From this line I expected that even the extremes of the scores should be integers. Or am I wrong?
Please Bunuel, help me out.
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Hi Kem12,

I think that you are confused by this: average= 9*1+1*9/10= 18/10= 1.8. Indeed it should be average= (9*1+1*9)/10= 18/10= 1.8. The second extreme is not a fraction.
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Kem12


Thanks for the explanation but the question says that each student in the class earned an INTEGER score... From this line I expected that even the extremes of the scores should be integers. Or am I wrong?
Please Bunuel, help me out.
Posted from my mobile device

Hi Kem12,

I think that you are confused by this: average= 9*1+1*9/10= 18/10= 1.8. Indeed it should be average= (9*1+1*9)/10= 18/10= 1.8. The second extreme is not a fraction.


Thanks. I now understand.
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