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Bunuel
Each of the even-numbered terms in a certain sequence is formed by multiplying the preceding term by –1. Each of the odd-numbered terms in the sequence is formed by adding 3 to the preceding term. If the first term in the sequence is 3, then what is the 168th term?

A. –3
B. –1
C. 0
D. 1
E. 3
Solution:

Let a_n be the nth term. We see that:

a_1 = 3
a_2 = -3
a_3 = 0
a_4 = 0
a_5 = 3
a_6 = -3
a_7 = 0
a_8 = 0

We see that the terms repeat in a four-number pattern: 3, -3, 0, 0. Note that the 4th and 8th terms are equal to 0, and any term number that is a multiple of 4 will also be equal to 0. Since 168 is a multiple of 4, the 168th term will be also equal to 0.

Answer: C
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