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Bunuel
If an integer is divisible by both 8 and 15, then the integer also must be divisible by which of the following?

A. 16

B. 24

C. 32

D. 36

E. 45

Let N be the number which is divisible by \(8(2^3)\) and \(15(3*5)\)

Therefore, Only Option B(\(24 = 2^3*3\)) divides the number N and is our answer.

P.S Prime-factorizing the remaining answer options gives us a higher power of the prime-numbers(in 8 and 15)
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Bunuel
If an integer is divisible by both 8 and 15, then the integer also must be divisible by which of the following?

A. 16

B. 24

C. 32

D. 36

E. 45

Since the LCM of 8 and 15 is 120, the integer is divisible by 120 and by any factors of 120. Since 24 is a factor of 120, the integer is divisible by 24.

Answer: B
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Bunuel
If an integer is divisible by both 8 and 15, then the integer also must be divisible by which of the following?

A. 16

B. 24

C. 32

D. 36

E. 45


The integer must be equal to the LCM of 8 and 15 which is 120.

24*5 = 120 . So, The correct answer is B as it is a factor of 120.
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