Events & Promotions
|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Apr 2711:00 AM EDT
-12:00 PM EDT
Prefer video-based learning? The Target Test Prep OnDemand course is a one-of-a-kind video masterclass featuring 400 hours of lecture-style teaching by Scott Woodbury-Stewart, founder of Target Test Prep and one of the most accomplished GMAT instructors
Apr 2808:00 AM PDT
-11:00 AM PDT
Whether you are just beginning your MBA journey or fine-tuning your path to a 700+ score, GMAT Day is designed to give you a competitive edge.
27 Jun 2018, 21:36
Kudos
Bookmarks
D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
25%
(medium)
Question Stats:
80% (01:46) correct
20%
(02:04)
wrong
based on 320
sessions
History
Date
Time
Result
Not Attempted Yet
Vinay and Phil are driving in separate cars to Los Angeles, both leaving from the same place and traveling along the same route. If Vinay leaves at 1 a.m. and travels at 40 miles per hour, and Phil leaves at 5 a.m. and travels at 50 miles per hour, at what time does Phil catch up to Vinay?
A. 1 p.m.
B. 5 p.m.
C. 7 p.m.
D. 9 p.m.
E. 11 p.m.
A. 1 p.m.
B. 5 p.m.
C. 7 p.m.
D. 9 p.m.
E. 11 p.m.
27 Jun 2018, 22:57
Kudos
Bookmarks
Solution
Given:
- • Vinay and Phil are driving in separate cars to Los Angeles, both leaving from the same place and traveling along the same route
• Vinay leaves at 1 a.m. and travels at 40 miles per hour
• Phil leaves at 5 a.m. and travels at 50 miles per hour
To find:
- • The time at which Phil catches up Vinay
Approach and Working:
When Phil started journey, Vinay already travelled for 4 hours
- • Hence, at 5 a.m., the distance between Phil and Vinay = 40 * 4 = 160 miles
5 a.m. onwards Vinay moved at 40 mph and Phil moved at 50 mph, at the same direction
- • So, in 1-hour time, the distance between them getting reduced by (50 – 40) = 10 miles
Therefore, to reduce the gap of 160 miles, they will take = \(\frac{160}{10}\) = 16 hours
- • So, they will meet 16 hours from 5 a.m., or at 9 p.m.
Hence, the correct answer is option D.
Answer: D
General Discussion
28 Jun 2018, 12:54
Kudos
Bookmarks
Vinay's distance covered before Phil started = 40*4 = 160 miles.
Let time taken by Phil to catch up Vinay be x.
Then, 50x = 40x + 160, x = 16.
Hence, time at which Phil was able to catch up = 5 a.m. + 16 = 9 p.m.
Let time taken by Phil to catch up Vinay be x.
Then, 50x = 40x + 160, x = 16.
Hence, time at which Phil was able to catch up = 5 a.m. + 16 = 9 p.m.
