Bunuel wrote:

Vinay and Phil are driving in separate cars to Los Angeles, both leaving from the same place and traveling along the same route. If Vinay leaves at 1 a.m. and travels at 40 miles per hour, and Phil leaves at 5 a.m. and travels at 50 miles per hour, at what time does Phil catch up to Vinay?

A. 1 p.m.

B. 5 p.m.

C. 7 p.m.

D. 9 p.m.

E. 11 p.m.

We can let Vinay’s time = t + 4 and Phil's time = t and create the equation:

Distance of Vinay = Distance of Phil

40(t + 4) = 50t

40t + 160 = 50t

160 = 10t

16 = t

Phil catches up to Vinay at 5 am + 16 hours = 9 pm.

Answer: D

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