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27 Jun 2018, 21:55
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B
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
15%
(low)
Question Stats:
81% (01:59) correct
19%
(02:16)
wrong
based on 311
sessions
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Integers a and b are consecutive multiples of 6. Integers x and y are consecutive multiples of 8. In terms of a, b, x, and y, what is the ratio of the average of a and b and the average of x and y?
A. \(\frac{(x+y)}{(a+b)}\)
B. \(\frac{(a+b)}{(x+y)}\)
C. \(\frac{(a+\frac{b}{4})}{(y-\frac{x}{4})}\)
D. \(\frac{(a+\frac{b}{4})}{(y-\frac{x}{2})}\)
E. \(\frac{1}{2}\frac{(a+b)}{(x+y)}\)
A. \(\frac{(x+y)}{(a+b)}\)
B. \(\frac{(a+b)}{(x+y)}\)
C. \(\frac{(a+\frac{b}{4})}{(y-\frac{x}{4})}\)
D. \(\frac{(a+\frac{b}{4})}{(y-\frac{x}{2})}\)
E. \(\frac{1}{2}\frac{(a+b)}{(x+y)}\)
27 Jun 2018, 23:03
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Solution
Given:
- • Integers a and b are consecutive multiples of 6
• Integers x and y are consecutive multiples of 8
To find:
- • In terms of a, b, x, and y, the ratio of the average of a and b and the average of x and y
Approach and Working:
- • The average of a and b = \(\frac{a+b}{2}\)
• The average of x and y = \(\frac{x+y}{2}\)
Therefore, the ratio of averages =\(\frac{a+b}{2}\) / \(\frac{x+y}{2}\) = \(\frac{a+b}{x+y}\)
Hence, the correct answer is option B.
Answer: B
Note: In an alternate way, we can also get the ratio by assuming values. For example, we can assume a =6, b = 12, and x = 8, y = 16. Putting this values in the option, we can check which one satisfies the answer.
28 Jun 2018, 03:17
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Bunuel
a and b are consecutive multiples of 6.
a = 6*1 = 6
b = 6*2 = 12
a+b = 18
a+b/2 = 18/2 = 9
x and y are consecutive integer of 8.
x = 8*1 = 8
y = 8*2 = 16
x+y = 24
x+y/ 2
= 24/2
=12
we are asked to find out the ratio of the average of a and b to x and y.
9 : 12
=3:4
Scan the answer choices by plugging in the value assumed above.
Only option B matches.
The best answer is B.
can you pls explain. thanks 
