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28 Jun 2018, 03:37
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B
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
35%
(medium)
Question Stats:
65% (01:25) correct
35%
(01:15)
wrong
based on 245
sessions
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Not Attempted Yet
[GMAT math practice question]
\(693\) and \(n\) have the same prime factors and \(n\) is a multiple of \(693\) that is greater than \(693\). What is the smallest possible value of \(\frac{n}{693}\)?
\(A. 2\)
\(B. 3\)
\(C. 5\)
\(D. 7\)
\(E. 11\)
\(693\) and \(n\) have the same prime factors and \(n\) is a multiple of \(693\) that is greater than \(693\). What is the smallest possible value of \(\frac{n}{693}\)?
\(A. 2\)
\(B. 3\)
\(C. 5\)
\(D. 7\)
\(E. 11\)
Updated on: 28 Jun 2018, 06:06
Originally posted by GMATGuruNY on 28 Jun 2018, 03:50.
Last edited by GMATGuruNY on 28 Jun 2018, 06:06, edited 1 time in total.
Last edited by GMATGuruNY on 28 Jun 2018, 06:06, edited 1 time in total.
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MathRevolution
\(693 = 3^2*7*11\)
Since n must have the same prime factors as 693 but must be greater than 693, the least possible option for \(n = 693 * 3\).
Thus, least possible value of \(\frac{n}{693} = \frac{(693*3)}{693} = 3\).
28 Jun 2018, 05:15
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MathRevolution
If the numbers n and 693 have the same prime factors and n is a multiple of 693,
the smallest value of \(\frac{n}{693}\) must be the smallest prime factor of 693.
693 when prime-factorized gives \(3^2*7*11\).
The minimum value of n is \(3*693\)(as n and 693 have same prime numbers)
Therefore, the smallest value of \(\frac{n}{693}\) is \(\frac{3*693}{693} = 3\)(Option B)
