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05 Jul 2018, 21:36
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C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
25%
(medium)
Question Stats:
78% (01:49) correct
22%
(01:55)
wrong
based on 127
sessions
History
Date
Time
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Not Attempted Yet
In the rectangular coordinate system above, if point (a, b), shown, and the two points (4a, b) and (2a, 2b), not shown, were connected by straight lines, then the area of the resulting triangular region, in terms of a and b, would be
(A) ab/2
(B) ab
(C) 3ab/2
(D) 2ab
(E) 4ab
Attachment:
20160425060058164.jpg [ 11.99 KiB | Viewed 3545 times ]
Hi,
Solve the determinant
1/2*
| x1 y1 1|
| x2 y2 1|
| x3 y3 1|
to get the area of the triangle. The answer comes out to be C
If you are not comfortable solving determinants, please use Area of triangle = 1/2∗|(x1y2−y1x2)+(x2y3−y2x3)+(x3y1−y3x1)|
Solve the determinant
1/2*
| x1 y1 1|
| x2 y2 1|
| x3 y3 1|
to get the area of the triangle. The answer comes out to be C
If you are not comfortable solving determinants, please use Area of triangle = 1/2∗|(x1y2−y1x2)+(x2y3−y2x3)+(x3y1−y3x1)|
05 Jul 2018, 21:58
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Bunuel
Given triangle with co-ordinates (a, b),(4a, b) and (2a, 2b).
length of base=4a-a=3a unit
length of height=2b-b=b unit
Area of triangle=\(\frac{1}{2}*base*height\)=\(\frac{1}{2}*3a*b\)=\(\frac{3ab}{2}\)
Ans. (C)
