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08 Jul 2018, 21:26
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A
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
25%
(medium)
Question Stats:
84% (02:04) correct
16%
(02:17)
wrong
based on 47
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Aquarium A holds 150 gallons more sea water than does Aquarium B, and both aquariums are currently filled to capacity. If 20 gallons are removed from each aquarium, then Aquarium A would hold four times as much sea water as Aquarium B holds. What is the combined total number of gallons of sea water that can be held in both aquariums?
A) 290
B) 250
C) 220
D) 200
E) 70
A) 290
B) 250
C) 220
D) 200
E) 70
09 Jul 2018, 01:59
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Water in A = X + 150
Water in B = X
Situation 2:
(x+150−20) = 4∗(x−20)
x+130 = 4x - 80
3x = 210
x = 70
Total capacity = x+(x+150) = 70+70+150 = 290
Therefore, the correct answer is Option A
Water in B = X
Situation 2:
(x+150−20) = 4∗(x−20)
x+130 = 4x - 80
3x = 210
x = 70
Total capacity = x+(x+150) = 70+70+150 = 290
Therefore, the correct answer is Option A
General Discussion
08 Jul 2018, 21:44
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Let x be the number of gallons in Aquarium B -> number of gallons in Aquarium A is x+150
If 20 gallons are removed from both the aquariums then the number of gallons in A is 4 times number of gallons in B
\(x+150-20 = 4*(x-20)\)
x = 70
Total capacity = x+x + 150 = 290
Hence Option A
If 20 gallons are removed from both the aquariums then the number of gallons in A is 4 times number of gallons in B
\(x+150-20 = 4*(x-20)\)
x = 70
Total capacity = x+x + 150 = 290
Hence Option A
