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Updated on: 30 Jul 2018, 02:40
Originally posted by bettatantalo on 30 Jul 2018, 02:24.
Last edited by Bunuel on 30 Jul 2018, 02:40, edited 1 time in total.
Last edited by Bunuel on 30 Jul 2018, 02:40, edited 1 time in total.
Renamed the topic, edited the question, added the OA and moved to PS forum.
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A
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
25%
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Question Stats:
70% (01:10) correct
30%
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wrong
based on 110
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The average (arithmetic mean) of the five numbers x, 91, 120, 134, and 220 is what percent of the sum of the five numbers?
(A) 20%
(B) 22%
(C) 25%
(D) 30%
(E) It cannot be determined from the information given.
(A) 20%
(B) 22%
(C) 25%
(D) 30%
(E) It cannot be determined from the information given.
30 Jul 2018, 02:43
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bettatantalo
The average of five numbers = (sum of the numbers)/5. So, the average of five numbers is 1/5, or 20% of the sum.
Answer: A.
30 Jul 2018, 22:45
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bettatantalo
You can either think logically and immediately choose the choice A or do algebraically and see the same result. In both cases, the logic plays a monumental role in this problem.
Finding Average: \(\frac{x+565}{5}\)
[b]The Sum x+565
The Sum is the total and the average is the part, so you can create an equation: \(\frac{x+565}{5}\) / x+565 = \(\frac{y%}{100%}\)
You can see that we have two variables x and y, but have only one equation. So, algebraically it's somehow impossible to find x and y. But you also can notice that you divide the numerator of the first fraction into 5, which in percent form is 100/5 yields 20%.
