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31 Jul 2018, 00:49
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E
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
5%
(low)
Question Stats:
97% (01:59) correct
3%
(01:13)
wrong
based on 77
sessions
History
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Time
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Not Attempted Yet
The wait time in minutes, w, for a table at a certain restaurant can be estimated by the formula \(w = d^2 + kn\), where d is the number of diners in the party, k is a constant, and n is the number of parties ahead in line at the beginning of the wait. If a party of 4 has an estimated wait time of 40 minutes when 6 other parties are ahead of it, how many minutes would the estimated wait time be for a party of 6 if there are 3 parties ahead of it?
(A) 28
(B) 33
(C) 39
(D) 42
(E) 48
(A) 28
(B) 33
(C) 39
(D) 42
(E) 48
31 Jul 2018, 01:06
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Bunuel
As the calculation we're asked to do is straightforward, we'll just do it.
This is a Precise approach.
We're told that when d = 4 and n = 6 then w = 40
Plugging this in gives 40 = 4^2 +6k --> k = 4
So, if d = 6 and n = 3, then w = 6^2 + 3*4 = 48
(E) is our answer.
31 Jul 2018, 03:27
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Bunuel
w = d^2 + kn
d = 4, n = 6, w = 40
On solving we get,
40 = 4^2 +6k
40 = 16 + 6k
6k = 24
k = 4
Again, for second case
d = 6, n = 3, k = 4
w = 6^2 + 3*4
w = 36 + 12
w = 48
Hence, E.
