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CAMANISHPARMAR
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If n is an integer and square_root(n^2-6n+9)=5, which of the ... 08 Aug 2018, 09:43
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Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!

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25% (medium)

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73% (01:45) correct 27% (02:00) wrong based on 401 sessions

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If n is an integer and \(\sqrt{(n^2-6n+9)}\)=5, which of the following could be the value of \((n + 3)^2\)?

A) –2
B) 1
C) 4
D) 11
E) 64
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B
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PKN
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If n is an integer and square_root(n^2-6n+9)=5, which of the ... 08 Aug 2018, 10:00
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CAMANISHPARMAR
If n is an integer and \(\sqrt{(n^2-6n+9)}\)=5, which of the following could be the value of \((n + 3)^2\)?

A) –2
B) 1
C) 4
D) 11
E) 64
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\(n^2-6n+9\) can be written as \((n-3)^2\)

Given, \(\sqrt{(n^2-6n+9)}\)=5
Squaring both sides, we have

\(n^2-6n+9=5^2\)
Or, \((n-3)^2=5^2\)
Or, \(|n-3|=5\)
So, n-3=5 or, n-3=-5
So, n=8 or, -2

Now, \((n+3)^2=(-2+3)^2=1^2=1\)
Or, \((n+3)^2=(8+3)^2=11^2=121\) (not in answer options)

Ans. (B)
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If n is an integer and square_root(n^2-6n+9)=5, which of the ... 09 Aug 2018, 03:52
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1. square both sides.
2.find x, which will be either 8 or -2.
3.substitute value, comes either 121 or 1.

4. 1 is correct answer.
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jfranciscocuencag
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If n is an integer and square_root(n^2-6n+9)=5, which of the ... 11 Feb 2019, 18:54
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CAMANISHPARMAR
If n is an integer and \(\sqrt{(n^2-6n+9)}\)=5, which of the following could be the value of \((n + 3)^2\)?

A) –2
B) 1
C) 4
D) 11
E) 64
Show more

Hello everyone!

I squared it but I have some doubt, what if I wouldn't want to square it?

What is wrong with the following?

\(\sqrt{(n^2-6n+9)}\)=5

\(\sqrt{(n - 3)(n - 3)}\)=5

\(\sqrt{(n - 3)^2}\)=5

If the GMAT gives you the squared root then you just consider the +ve option.

\((n - 3)\)=5

n = 8

Thank you so much in advance!!!
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krushal95
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If n is an integer and square_root(n^2-6n+9)=5, which of the ... 06 Jan 2021, 04:26
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PKN
CAMANISHPARMAR
If n is an integer and \(\sqrt{(n^2-6n+9)}\)=5, which of the following could be the value of \((n + 3)^2\)?

A) –2
B) 1
C) 4
D) 11
E) 64
Show more

Hi.

Or, \(|n-3|=5\) --> How did you get this function
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KarishmaB
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If n is an integer and square_root(n^2-6n+9)=5, which of the ... 06 Jan 2021, 06:06
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jfranciscocuencag
CAMANISHPARMAR
If n is an integer and \(\sqrt{(n^2-6n+9)}\)=5, which of the following could be the value of \((n + 3)^2\)?

A) –2
B) 1
C) 4
D) 11
E) 64

Hello everyone!

I squared it but I have some doubt, what if I wouldn't want to square it?

What is wrong with the following?

\(\sqrt{(n^2-6n+9)}\)=5

\(\sqrt{(n - 3)(n - 3)}\)=5

\(\sqrt{(n - 3)^2}\)=5

If the GMAT gives you the squared root then you just consider the +ve option.

\((n - 3)\)=5

n = 8

Thank you so much in advance!!!
Show more

The part after the red part is not correct.

\(\sqrt{x^2} = |x|\)

The square root has only the positive value, that is true. That is why the square root is the absolute value of x. It will never be negative. But x can take a negative value here.

Say
\(\sqrt{x^2} = 2\)

x can be 2 or -2 here. Try to put 2 or -2. In either case, we will get \(\sqrt{x^2} = 2\).

But if we are given \(\sqrt{4}\), the value of that is of course only 2.
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If n is an integer and square_root(n^2-6n+9)=5, which of the ... 26 Sep 2023, 13:01
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